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How much competition does a tender for IT services in Czechia face?

A median of 1 bid per procedure; 54% of procedures ended with a single bidder (4,188 awards with a bid count). National average for Czechia across all sectors: 3.5 bids.

Search open tenders in this sector · Country guide Czechia

The market norm in numbers

MetricSectorNational averageSample
Bids per procedure (median)13.54,188
Procedures with a single bidder54%30%4,188
Awards to a repeat winner60%68%5,284
Distinct winners1,07221,9825,364
Awards to companies from abroad7%8%5,364
Award relative to estimate (median)87%86%1,030
Bids from SMEs66%77%3,728
Bids from abroad2%2%3,728

How to read these numbers

Of 42 sectors in Czechia with a bid count, IT services ranks 35 for competition. Every second tender effectively ends without competition — showing up often wins. 60% of awards went to companies that had already won with the same buyer — the incumbent is the rule, newcomers need a price or quality edge.

Other sectors in the same country

Frequently asked questions

How many bidders does a tender for IT services in Czechia get?

A median of 1 bid per procedure, measured on 4,188 awards with a bid count since 2013. 54% of procedures had a single bidder.

How often does the incumbent win in Czechia?

60% of awards in IT services went to a company that had already won with the same buyer.

Do foreign companies stand a chance in Czechia for IT services?

7% of awards went to companies based outside Czechia.

What share of the estimate does the winner get in IT services?

The award came in at a median 87% of the estimated value.

Where the numbers come from

From the documented awards of every portal we read (TED and the national portals), aggregated every night. Bid counts come from the award notices themselves (TED BT-759, PLACSP, OCDS, Hilma, ANAC); incumbency counts whether the winner had won with the same buyer before; abroad means the winner's country differs from the buyer's. Metrics below the minimum sample are not shown.

As of 25/10/2026 · n = 5,364