Friedrich & ClementBETA

Guide · Back to the overview

How much competition does a tender for Construction work in Luxembourg face?

A median of 4 bids per procedure; 15% of procedures ended with a single bidder (360 awards with a bid count). National average for Luxembourg across all sectors: 7.1 bids.

Search open tenders in this sector · Country guide Luxembourg

The market norm in numbers

MetricSectorNational averageSample
Bids per procedure (median)47.1360
Procedures with a single bidder15%16%360
Awards to a repeat winner17%23%520
Distinct winners3761,812537
Awards to companies from abroad7%35%537
Award relative to estimate (median)–76%0
Bids from SMEs–63%0
Bids from abroad–59%0

How to read these numbers

Of 7 sectors in Luxembourg with a bid count, Construction work ranks 5 for competition. Competition is dense — the calculation decides. 17% of awards went to companies that had already won with the same buyer — buyers switch often here.

Other sectors in the same country

Frequently asked questions

How many bidders does a tender for Construction work in Luxembourg get?

A median of 4 bids per procedure, measured on 360 awards with a bid count since 2022. 15% of procedures had a single bidder.

How often does the incumbent win in Luxembourg?

17% of awards in Construction work went to a company that had already won with the same buyer.

Do foreign companies stand a chance in Luxembourg for Construction work?

7% of awards went to companies based outside Luxembourg.

What share of the estimate does the winner get in Construction work?

The sample in this sector is not large enough yet.

Where the numbers come from

From the documented awards of every portal we read (TED and the national portals), aggregated every night. Bid counts come from the award notices themselves (TED BT-759, PLACSP, OCDS, Hilma, ANAC); incumbency counts whether the winner had won with the same buyer before; abroad means the winner's country differs from the buyer's. Metrics below the minimum sample are not shown.

As of 25/10/2026 · n = 537